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-.9x^2+6x-5.7=0
We add all the numbers together, and all the variables
-0.9x^2+6x-5.7=0
a = -0.9; b = 6; c = -5.7;
Δ = b2-4ac
Δ = 62-4·(-0.9)·(-5.7)
Δ = 15.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{15.48}}{2*-0.9}=\frac{-6-\sqrt{15.48}}{-1.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{15.48}}{2*-0.9}=\frac{-6+\sqrt{15.48}}{-1.8} $
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